Answer:
[tex]24.9~g/cm^3[/tex]
Explanation:
Density is found dividing mass by volume. In this case, we treat krypton as a sphere having a volume of [tex]V = \dfrac{4}{3}\pi r^3[/tex]. Given:
[tex]m = 1.39\cdot 10^{-22}~g[/tex]
[tex]r = 110 pm = 1.10\cdot 10^{-8}~cm[/tex]
We obtain density of:
[tex]d = \dfrac{m}{V} = \dfrac{m}{\dfrac{4}{3}\pi r^3} = \dfrac{3m}{4\pi r^3}[/tex]
[tex]d = \dfrac{3\cdot 1.39\cdot 10^{-22}~g}{4\pi\cdot (1.10\cdot 10^{-8}~cm)^3} = 24.9~g/cm^3[/tex]
This is not a feasible value for a gas like krypton, its radius is actually not 110 pm.
