Question:
Daniel had $25 to spend at the fair. If the admission to the fair is $4 and the rides cost $1.50 each, write an inequality that represent Daniels situation what is the greatest number of rides daniel can go on?
Answer:
The inequality that represents Daniel situation is:
[tex]4 + 1.50x\leq 25[/tex]
The greatest number of rides Daniel can go is 14
Solution:
Daniel had $25 to spend at the fair
Total amount with Daniel = $ 25
Admission price = $ 4
Cost of 1 ride = $ 1.50
Let "x" be the number of rides
Then cost of "x" rides is 1.50x
Then, we frame a inequality as:
Admission price + cost of "x" ride [tex]\leq[/tex] 25
[tex]4 + 1.50x\leq 25[/tex]
Here we used "less than or equal to" symbol, because he can spend maximum upto 25 dollars
Solve for "x"
[tex]4 + 1.50x\leq 25\\\\1.50x \leq 25 -4\\\\1.50x\leq 21\\\\Divide\ both\ sides\ by\ 1.50\\\\x\leq 14[/tex]
Thus greatest number of rides is 14
