The current in the 2nd case is 102 A
Step-by-step explanation:
The relationship between voltage, current and resistance in an electric circuit is given by Ohm's law:
[tex]V=IR[/tex]
where
V is the voltage
I is the current
R is the resistance
In this problem we are given two sets of data for the current and the resistance, while the voltage is kept constant. This means that we can write:
[tex]V_1=V_2\\I_1 R_1 = I_2 R_2[/tex]
where
[tex]I_1 = 60 A[/tex] is the current in the 1st case
[tex]R_1 = 255 \Omega[/tex] is the resistance in the 1st case
[tex]R_2 = 150 \Omega[/tex] is the resistance in the 2nd case
Solving for [tex]I_2[/tex], we find the current in the 2nd case:
[tex]I_2 = \frac{I_1 R_1}{R_2}=\frac{(60)(255)}{150}=102 A[/tex]
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