Answer:
Empirical formula is Fe₂O₃.
Explanation:
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number.
Given data:
Mass of iron = 4.166 g
Mass of oxygen = 1.803 g
Empirical formula = ?
Solution:
Number of gram atoms of Fe = 4.166 / 55.845 = 0.075
Number of gram atoms of O = 1.803 / 15.999 = 0.113
Atomic ratio:
Fe : O
0.075/0.075 : 0.113/0.075
1 : 1.5
Fe : O = 1 : 1.5
Fe : O = 2(1 : 1.5)
Empirical formula is Fe₂O₃.
