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A guy wire runs from the ground to a cell tower. The wire is attached to the cell tower 150 feet above the ground. The angle formed between the wire and the ground is 44° (see figure). (Round your answers to one decimal place.)


(a) How long is the guy wire?

(Answer in feet)


(b) How far from the base of the tower is the guy wire anchored to the ground?

(Answer in feet)

A guy wire runs from the ground to a cell tower The wire is attached to the cell tower 150 feet above the ground The angle formed between the wire and the groun class=

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The length of guy wire is: 215.92 feet

And the distance between the tower and anchor if guy wire is: 155.32 feet

Step-by-step explanation:

Given scenario forms a right triangle where the height of tower is perpendicular and the length of guy wire is hypotenuse while the distance between tower and anchor of guy wire is base

We only know the perpendicular and the angle.

Angle = 44°

So,

Now

Let g be the length of guy wire

Then

[tex]sin\ 44 = \frac{height\ of\ tower}{length\ of\ guy\ wire}\\0.6947 = \frac{150}{g}\\g = \frac{150}{0.6947}\\g = 215.92\ ft[/tex]

Now for the distance between tower and anchor of guy wire

Let d be the required distance

[tex]tan\ 44 =\frac{Height\ of\ tower}{Distance\ between\ anchor\ and\ tower}\\0.9657 = \frac{150}{d}\\d = \frac{150}{0.9657}\\d = 155.32\ ft[/tex]

Hence,

The length of guy wire is: 215.92 feet

And the distance between the tower and anchor if guy wire is: 155.32 feet

Keywords: Triangle, ratios

Learn more about triangle at:

  • brainly.com/question/4703807
  • brainly.com/question/4703820

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