Yes, it is safe to operate the circuit, before the power dissipated is less than the maximum power
Explanation:
For a resistor, the power rating gives the maximum power at which the resistor is safe to operate.
For the resistor in this problem, this maximum power is given and it is
[tex]P_{max}=\frac{1}{4}W=0.25 W[/tex]
The power dissipated on a resistor can be calculated with the equation
[tex]P=\frac{V^2}{R}[/tex]
where
V is the potential difference applied on the resistor
R is the resistance
In this problem, we have:
[tex]V=12 V\\R=10 k\Omega = 10,000 \Omega[/tex]
therefore, the power dissipated on the resistor is:
[tex]P=\frac{12^2}{10,000}=0.014 W[/tex]
Which is less than the maximum power: therefore, yes, it will be safe to operate the circuit.
Learn more about power and resistance:
brainly.com/question/4438943
brainly.com/question/10597501
brainly.com/question/12246020
#LearnwithBrainly
