Step-by-step explanation:
[tex]c(n) = \frac{4}{9} ( - 3)^{n - 1} \\ \\ \therefore \: c(3) = \frac{4}{9} ( - 3)^{3- 1} \\ \\ \therefore \: c(3) = \frac{4}{9} ( - 3)^{2} \\ \\ \therefore \: c(3) = \frac{4}{9} \times 9 \\ \\ \huge{ \purple{ \boxed{\therefore \: c(3) = 4}}}[/tex]
The 3rd term in the sequence is 4 after plugging the n = 3 in the nth term of the sequence.
It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
We have the nth term of a sequence:
[tex]\rm c(n) = \dfrac{4}{9}(-3)^{n-1}[/tex]
Plug n = 3
[tex]\rm c(3) = \dfrac{4}{9}(-3)^{3-1}[/tex]
c(3) = (4/9)(9)
c(3) = 4
Thus, the 3rd term in the sequence is 4 after plugging the n = 3 in the nth term of the sequence.
Learn more about the sequence here:
brainly.com/question/21961097
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