Answer: 20 meters
Explanation:
This situation is related to vertical motion, especifically an object in free fall, and the parametric equation that describes this motion is:
[tex]y=y_{o}+V_{o}t-\frac{g}{2}t^{2}[/tex]
Where:
[tex]y= 0 m[/tex] is the stone's final height
[tex]y_{o}[/tex] is the stone's initial height
[tex]V_{o}=0 m/s[/tex] is the initial speed of the stone
[tex]t=2 s[/tex] is the time the stone is falling
[tex]g=10 m/s^{2}[/tex] is the acceleration due gravity
Isolating [tex]y_{o}[/tex] according to the given information:
[tex]y_{o}=\frac{g}{2}t^{2}[/tex]
[tex]y_{o}=\frac{10 m/s^{2}}{2}(2 s)^{2}[/tex]
Finally:
[tex]y_{o}=20 m[/tex] This is the distance the stone fell