A solution is prepared by dissolving calcium chloride in water and diluting to 500.0 mL. If this solution contains 44 ppm chloride ions, the concentration of calcium ions is how many ppm?
a) 44
b) 88
c) 22
d) 11
e) 500

Respuesta :

Answer:

The answer is c) 22 ppm

Explanation:

The dissolution of calcium chloride in water as below,

CaCl₂ ⇒ Ca²⁺ + 2Cl⁻

Clearly, in aqueous solution, the concentration of chloride ions always double the concentration of calcium ion. So, in our case, the chloride ions concentration is 44 ppm, the calcium ion will be 22 ppm.

ppm is part per million, which is based on the molecule concentration, so we can quickly use the molar stoichiometry ratio to find out the answer.

The concentration of calcium ions in the solution will be 22 ppm. Thus, option C is correct.

Calcium chloride has been the molecular compound with two chloride ions and one calcium ion.

The dissociation of the calcium chloride in water results in the chloride ion being double the calcium ions.

The solution of Calcium chloride has been dissociated in the 500 ml water.

The concentration of chloride ions = 44 ppm.

The concentration of calcium ions = [tex]\rm \dfrac{Cl^-}{2}[/tex]

The concentration of calcium ions = [tex]\rm \dfrac{44}{2}[/tex]

The concentration of calcium ions = 22 ppm.

The concentration of calcium ions in the solution will be 22 ppm. Thus, option C is correct.

For more information about dissolving calcium chloride, refer to the link:

https://brainly.com/question/22875696

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