Answer:
Electric flux [tex]\phi=31562.63\ Nm^2/C[/tex]
Explanation:
Given that,
Electric field acting on the circular area, [tex]E=(4000j+3000k)\ N/C[/tex]
We need to find the electric flux through a circular area of radius 1.83 m that lies in the xy-plane. It lies in xy plane, such that the area vector point in z direction. The electric flux is given by :
[tex]\phi=E{\cdot}A[/tex]
[tex]\phi=(4000j+3000k){\cdot}Ak[/tex]
Using dot product properties, we get the value of electric flux as :
[tex]\phi=3000\times Ak[/tex]
[tex]\phi=3000\times \pi (1.83)^2[/tex]
[tex]\phi=31562.63\ Nm^2/C[/tex]
So, the electric flux through a circular area is [tex]\phi=31562.63\ Nm^2/C[/tex] . Hence, this is the required solution.