Answer:
Option A 90,68
[tex]m\angle 1=90^o[/tex]
[tex]m\angle 2=68^o[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
The figure shows a kite
we know that
A kite properties include
1) two pairs of consecutive, congruent sides
2) congruent non-vertex angles
3) perpendicular diagonals
Find the measure of angle 1
we have that
[tex]m\angle 1=90^o[/tex] ----> by the diagonals are perpendicular
Find the measure of angle 2
we know that
triangle AEB is congruent with triangle CEB
so
[tex]m\angle EAB=m\angle ECB=m\angle 2[/tex]
In the right triangle EAB
[tex]m\angle EAB+22^o=90^o[/tex] ----> by complementary angles in a right triangle
so
[tex]m\angle EAB=90^o-22^o=68^o[/tex]
therefore
[tex]m\angle 2=68^o[/tex]