Answer:
The value of "a" in the given system of equations is 16
Therefore a=16
Therefore substitute a=16 then equation (2) becomes
12x-8y=2(16)
12x-8y=32
Step-by-step explanation:
Given system of equations are [tex]3x-2y=8\hfill (1)[/tex]
and [tex]12x-8y=2a\hfill (2)[/tex] have infinite number of solutions
To find the value of a in the given system of equations :
From given the equations have infinite number of solutions and so they refers the same line
Therefore the equation (2) becomes
[tex]12x-8y=2a[/tex]
[tex]4(3x-2y)=2a[/tex]
[tex]4(8)=2a[/tex] ( by [tex]3x-2y=8[/tex] )
[tex]32=2a[/tex]
[tex]\frac{32}{32}=\frac{2a}{32}[/tex]
[tex]1=\frac{a}{16}[/tex]
[tex]1\times 16=\frac{a}{16}\times 16[/tex]
[tex]16=a[/tex]
Rewritting the above equation we get
[tex]a=16[/tex]
The value of "a" in the given system of equations is 16
Therefore a=16
Therefore equation (2) becomes
12x-8y=2(16)
12x-8y=32
