Answer:
[tex]w=0.5534rad/s[/tex]
Explanation:
Given data
Diameter d=64.0 m
To find
Angular velocity ω
Solution
From Centripetal acceleration we know that
[tex]a=g=\frac{v^{2} }{R}[/tex]
As we know that angular velocity ω as
[tex]w=v/R\\v=wR[/tex]
So
[tex]g=\frac{v^{2} }{R}\\g=\frac{(wR)^{2} }{R}\\ g=\frac{w^{2}R^{2} }{R}\\g=w^{2}R\\w^{2}=\frac{g}{diameter/2}\\w^{2}=\frac{9.8m/s^{2}}{(64/2)m}\\w^{2}=0.30625\\w=\sqrt{0.30625}\\ w=0.5534rad/s[/tex]
