A rope of negligible mass is stretched horizontally between two supports that are 9.56 m apart. When an object of weight 4140 N is hung at the center of the rope, the rope is observed to sag by 36.2 cm. What is the tension in the rope?

Respuesta :

Answer:

The tension in the rope is 27416.9 N.

Explanation:

Given that,

Distance = 9.56 m

Weight of object = 4140 N

Length =36.2 cm

We need to calculate the angle

Using formula of angle

[tex]\tan\theta=\dfrac{y}{x}[/tex]

[tex]\theta=\tan^{-1}(\dfrac{y}{x})[/tex]

Put the value into the formula

[tex]\theta=\tan^{-1}(\dfrac{0.362}{4.78})[/tex]

[tex]\theta=4.33^{\circ}[/tex]

We need to calculate the tension in the rope

Using balance equation

[tex]2T\sin\theta=W[/tex]

[tex]T=\dfrac{W}{2\sin\theta}[/tex]

Put the value into the formula

[tex]T=\dfrac{4140}{2\sin4.33}[/tex]

[tex]T=27416.9\ N[/tex]

Hence, The tension in the rope is 27416.9 N.

Ver imagen CarliReifsteck