Answer:
The heat = 2.63 kJ (option d)
Explanation:
Step 1: Data given
Mass of ethanol = 125 grams
Initial temperature of ethanol = 22.3 °C
Final temperature of ethanol = 31.0 °C
Specific heat of ethanol = 2.42 J/g°C
Step 2: Calculate heat transfer
Q = m*c*ΔT
⇒ with Q = the heat transfer (in joules)
⇒ with m = the mass of ethanol = 125 grams
⇒ with c = the specific heat of ethanol = 2.42 J/g°C
⇒ with ΔT = The change of temeprature = T2 - T1 = 31.0 - 22.3 °C = 8.7 °C
Q = 125 grams * 2.42 J/g°C * 8.7 °C
Q = 2632 J = 2.63 kJ
The heat = 2.63 kJ (option d)
