Explanation:
In throttling process, [tex]h_{1}[/tex] is approximately equal to [tex]h_{12[/tex]
For state 1 :
[tex]P_{1}[/tex] = 550 kPa, [tex]h_{1}[/tex] = 2853.3 kJ/kg
[tex]T_{1} = 200^{o}C[/tex], [tex]\nu[/tex] = 2641.4 kJ/kg
For state 2:
[tex]P_{2}[/tex] = 200 kPa, [tex]h_{1} = h_{2}[/tex] = 2853.3 kJ/kg
[tex]T_{2} = 191.33^{o}C[/tex], [tex]\nu[/tex] = 2641.3 kJ/kg
As the value of [tex]T_{2}[/tex] is [tex]191.33^{o}C[/tex] so it is superheated.
Change in internal energy will be calculated as follows.
[tex]\Delta U = U_{2} - U_{1}[/tex]
= 2641.3 - 2641.4
= -0.1 kJ/kg
Hence, we can conclude that change in internal energy is 0.1 kJ/kg.
