Answer:
Explanation:
It is given that the ball is lodged in a hole in the floor of merry-go-round that is running at a constant speed.
Now the ball is moving a vertical circular motion
The position of the ball changes w.r.t to the center as it moves in a circular path i.e. vectorially it changes but its magnitude will remain the same.
The velocity of the ball is the same as merry-go-round so its magnitude remains the same but its direction will change continuously.
As the ball is moving in a circular path so a centripetal acceleration will acts towards the center so its value will be continuously changing.