x= -0.25 and 1.25
x = -0.5 and 1.5
x = 0 and 1
x = -0.375 and 1.625
Step-by-step explanation:
Given equation of the curve is
[tex]y = 4x^2 -4x-1[/tex]
(i)
First equation [tex]4x^2 -4x-1 =0[/tex]
Here y = 0
In x-axis the value of y = 0
The graph cuts the x-axis at(-0.25,0) and (1.25,0)
So, x= -0.25 and 1.25
(ii)
[tex]4x^2 -4x-1 =2[/tex]
here y = 2
The line y= 2 cuts the curve at (-0.5,2) and (1.5,2)
So, x = -0.5 and 1.5
Given equation of the curve is
[tex]y= 3x^2-3x -1[/tex]
(i)
[tex]3x^2-3x +2 =2[/tex]
[tex]\Leftrightarrow 3x^2-3x -1 = -1[/tex]
Here y = -1
The line y = -1 cuts the curve at (0,-1) and (1,-1)
So x = 0 and 1
(ii)
[tex]3x^2-3x -1 =x+1[/tex]
Here y = x+1
The line y -x =1 cuts the curve at (-0.375,0.5) and (1.625,2).
So x = -0.375 and 1.625
