Answer:
The subscripts in the molecular formula are 16 for C, 28 for H and 4 for O
Explanation:
Let's work with the mass of compound and the percentage composition.
100 g of compound has 67.57 g of C, 9.92 g of H and 22.5 g of O
To find out in the molecular weight we must make a rule of three:
100 g of compound has 67.57 g of C, 9.92 g of H and 22.5 g of O
Then 284.4 g of compound would have:
(284.4 . 67.57) /100 = 192 g of C
(284.4 . 9.92) /100 = 28 g of H
(284.4 . 22.5) /100 = 64 g of O
We have to divide each mass, to determine the moles of each element
192 g / 12 g/mol = 16 mol C
28 g / 1 g/mol = 28 mol H
64 g / 16 g/mol = 4 mol O
The subscripts in the molecular formula are 16 for C, 28 for H and 4 for O
