Answer:
a)[tex]a= 1.6 m/s^2[/tex]
b)V= 24 m/s
c)d=240 m
Explanation:
Given that
u = 16 m/s
v= 32 m/s
t= 10 s
The average acceleration = a
We know v = u +at
32 = 16 + a x 10
[tex]a=\dfrac{32-16}{10}\ m/s^2[/tex]
[tex]a= 1.6 m/s^2[/tex]
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
d=displacement
[tex]d=16\times 10+\dfrac{1}{2}\times 1.6\times 10^2[/tex]
d=240 m
The average velocity
[tex]V=\dfrac{d}{t}[/tex]
[tex]V=\dfrac{240}{10}\ m/s[/tex]
V= 24 m/s
a)[tex]a= 1.6 m/s^2[/tex]
b)V= 24 m/s
c)d=240 m
