Respuesta :
Answer:
[tex]Vitaminc\text{ }C:73.8\%\\ \\ Sucralose:26.2\%[/tex]
Explanation:
1. Molar masses of the two compounds
i) Vitamin C:
Formula: C₆H₈O₆
- Molar mass: 176.13 g/mol
ii) Sucralose
- Formula: C₁₂H₁₉Cl₃O₈
- Molar mass: 397.64 g/mol
2. Molarity of the solution:
The osmotic pressure is a colligative property which can be calculated using the following equation:
[tex]\Pi =MRT[/tex]
Where:
- Π is osmotic pressure (atm) = 3.04 atm
- M is the molar concentration of dissolved species (mol/L).
- R is the ideal gas constant = 0.08206 L-atm/mol- K
- T is the temperature (Kelvin) = 295 K
You can solve for M:
[tex]M=\Pi/(RT)=\frac{3.04atm}{0.08206(atm\times L/K\times mol)\times295K}\\ \\ M=0.1256[/tex]
3. Number of moles
You can calculate the number of moles of the dissolved species using the formula:
[tex]M=number \text{ }of \text{ }moles/volume(in\text{ }liters)}[/tex]
[tex]0.1256M=number \text{ }of \text{ }moles/0.0434L\\\\number \text{ }of \text{ }moles=0.1256M\times 0.0434L=0.0054502mol[/tex]
3. Equation to find moles of each compound
Number of moles of each compound:
i) Vitamin C
Let x be the mass in grams of vitamin C in the 1.124g sample. Then, 1.124g - x is the mass of sucralose.
- Number of moles = mass in grams / molar mass
- Number of moles = x / 176.13 g/mol = x / 176.13
ii) Sucralose
- Number of moles = (1.124g - x) / 397.64 g/mol = (1.124 - x / 397.64)
iii) Total moles equation:
[tex]x/176.13+(1.124-x)/397.64=0.0054502[/tex]
- Solve for x:
[tex]x=0.8295[/tex]
Then,
[tex]1.124-x=0.2945[/tex]
And the mass percent of vitamin C and sucralose are:
[tex]Vitaminc\text{ }C:0.8295g/1.124g\times 100=73.8\%\\ \\ Sucralose:0.2945g/1.124g\times 100=26.2\%[/tex]