Answer:
17.41°C is the change in temperature of the aluminum block.
Explanation:
Latent heat of fusion water = 334 J/g
Heat required to freeze 1 gram of water = -334 J
Heat required to freeze 2.58 grams of water = Q
[tex]Q=2.58 g\times (-334 J/g)=-861.72 J[/tex]
Heat lost by water will be equal to heat gained by the aluminum block
[tex]Q'=-Q[/tex]
[tex]Q'= -(-861.72 J)=861.72 J[/tex]
Formula used to calculate heat absorbed by substance:
[tex]Q=mc\Delta T[/tex]
Where:
Q = heat absorbed by substance
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
We have :
Mass of aluminum block= m= 55 g
Heat capacity of aluminum = c = 0.9 J/g°C
Change in temperature of the aluminum block= ΔT = ?
Heat absorbed by the aluminum = Q'
[tex]861.72 J=55 g\times 0.9 J/g^oC\times \Delta T[/tex]
[tex]\Delta T=17.41 ^oC[/tex]
17.41°C is the change in temperature of the aluminum block.
We have that the change in temperature of the aluminum block. is mathematically given as
dt=17.408C
From the question we are told
Generally the equation for the Heat is mathematically given as
Q=mL_1
Therefore
Q=(2.58(3.34))
Q=861.72J
Where
Heat Loss =Heat gain
861.72J=(55)(0.9)dt
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