Answer:
$5837 approx
Explanation:
Amount = [tex]Principal(1\ +\ r)^{n}[/tex]
Amount deposited at the end of year 1 would yield = $2500 [tex](1\ +\ .09)^{4}[/tex] = $2500 × 1.41158 = $3528.95
Amount deposited at the end of year year 3 would yield = $750 [tex](1\ +\ .09)^{2}[/tex] = $891.075
Amount deposited at the end of year 4 would yield = $1300 [tex](1\ +\ .09)^{1}[/tex] = $1417
Total deposit at the end of year 5 = $3528.95 + $891.075 + $1417 = $5837 approx.