Answer: The probability is 51.28%
Step-by-step explanation:
We know that out of 100% of the drivers, an 82% where stoped.
of these 84% stoped, 34% receive a blood test and 24% receive both tests, so a total of 58% received at least one test.
then, out of the 100% of the drivers, the ones that received at least a test are:
0.84*0.58 = 0.4872
So a 48.72% of the drivers received at least one test, this means that if one random driver is selected, the probability that the driver did not receive either test is 100% - 48.72% = 51.28%
