Answer:
[tex]2.518\times 10^{-23} J[/tex] is the energy of one photon of this radiation.
Explanation:
[tex]E=h\nu =\frac{h\times c}{\lambda}[/tex]
where,
E = energy of photon
h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]
c = speed of light = [tex]3\times 10^8m/s[/tex]
[tex]\nu [/tex] = Frequency of the radiation
[tex]\lambda[/tex] = wavelength of the radiation":
We have :
[tex]\nu = 3.8\times 10^{10} Hz=3.8\times 10^{10} s^{-1}[/tex]
Energy of the photon of the radiation :
[tex]E=6.626\times 10^{-34}Js\times 3.8\times 10^{10} s^{-1}[/tex]
[tex]E=2.518\times 10^{-23} J[/tex]
[tex]2.518\times 10^{-23} J[/tex] is the energy of one photon of this radiation.
