Answer: 160.4040
Step-by-step explanation:
Here , the claim is "The standard deviation of pulse rates of adult males is more than 11 bpm." , i.e. [tex]\sigma>11[/tex]
We use Chi-square test statistic for the test statistic to test the standard deviations :
[tex]\chi^2=\dfrac{(n-1)s^2}{\sigma^2}[/tex] , where s= sample standard deviation , [tex]\sigma[/tex] = population standard deviations and n = sample size.
As per given , n=153 , s= 11.3
Then, Required test statistic will be :
[tex]\chi^2=\dfrac{(153-1)(11.3)^2}{11^2}=\dfrac{152\times127.69}{121}\approx160.4040[/tex]
Hence, the value of the test statistic. = 160.4040