Respuesta :
Answer:
150000000
[tex]\dfrac{F_e}{F_g}=0.00000203873598369[/tex]
49050000 N/C
Explanation:
q = Charge = 24 pC
m = Mass of honeybee = 0.12 g
E = Electric field = 100 N/C
g = Acceleration due to gravity = 9.81 m/s²
[tex]1\ C=6.25\times 10^{18}\ electrons[/tex]
Number electrons is
[tex]n=24\times 10^{-12}\times 6.25\times 10^{18}\\\Rightarrow n=150000000[/tex]
The number of electrons added or removed was 150000000
Force is given by
[tex]F_e=Eq\\\Rightarrow F_e=100\times 24\times 10^{-12}\\\Rightarrow F_e=2.4\times 10^{-9}\ N[/tex]
The ratio is
[tex]\dfrac{F_e}{F_g}=\dfrac{2.4\times 10^{-9}}{0.12\times 10^{-3}\times 9.81}\\\Rightarrow \dfrac{F_e}{F_g}=0.00000203873598369[/tex]
The ratio is [tex]\dfrac{F_e}{F_g}=0.00000203873598369[/tex]
Balancing the forces we get
[tex]Eq=mg\\\Rightarrow E=\dfrac{mg}{q}\\\Rightarrow E=\dfrac{0.12\times 10^{-3}\times 9.81}{24\times 10^{-12}}\\\Rightarrow E=49050000\ N/C[/tex]
The electric field required is 49050000 N/C
The ratio of the electric force on the bee to the bee’s weight (Fe/Fg) is; 2.041 * 10⁻⁶
The electric field strength is; 4.9 * 10⁷ N/C
What is the electric field strength?
We are given;
Mass of bee; m = 0.12g = 0.00012 kg
Charge acquired by the bee q = +24 pC = 24 * 10⁻¹² C
Electric field; E = 100 N/C
B) The force F on a charge in electric field E is given by:
F = qE
F = 24 * 10⁻¹² * 100
F = 24 * 10⁻¹⁰ N
Weight is;
F_g = mg
F_g = 0.00012 * 9.8
F_g = 11.76 × 10⁻⁴ N
Ratio of force to weight is;
F_e/F_g = (24 * 10⁻¹⁰)/(11.76 × 10⁻⁴)
F_e/F_g = 2.041 * 10⁻⁶
C) To get the electric field strength, we will use the formula;
E' = mg/q
E' = (0.00012 * 9.8)/(24 * 10⁻¹²)
E' = 4.9 * 10⁷ N/C
Read more about Electric Field strength at; https://brainly.com/question/14473279
