The coordinates of where diagonals AC and BD intersect at O(2,7).
Step-by-step explanation:
We are given coordinates as A(-1,10) and C(5,4).And we know that the diagonals of parallelogram always bisect each other.
Let us consider O is the intersection point among the diagonals AC and BD. So, the point O bisects the line AC into two equal parts, and also it is the mid-point of AC.
We can find point O using the midpoint formula as,
O (x,y) = ([tex]\frac{(x1+x2)}{2}[/tex] , [tex]\frac{(y1+y2)}{2}[/tex])
= ([tex]\frac{(-1+5)}{2}[/tex] , [tex]\frac{(10+4)}{2}[/tex])
= ([tex]\frac{4}{2}[/tex], [tex]\frac{14}{2}[/tex])
= (2,7)
So Diagonals AC and BD intersects at the point O (2,7).
