Answer:
Molality of solution = 0.973 m
Explanation:
Molality : It is defined as the moles of the solute per Kg mass of solvent.It is not temperature dependent.
Solute = Substance which is present in less quantity in the solution is called the solute. Here , Sucrose is the solute.
Solvent = Substance which is present in more quantity is the solvent. Here water is solvent.
[tex]Molality=\frac{moles\ of\ solute}{mass\ of\ solvent}[/tex]
Density = It is defined as the mass per unit volume.
[tex]Density=\frac{mass}{Volume}[/tex]
Mass of Solute = 137.9 g
[tex]Moles=\frac{mass}{Molar\ mass}[/tex]
Molar mass of sucrose =
[tex]C_{12}H_{22}O_{11}[/tex]= 12(mass of C)+22(mass of H)+11(mass of O)
= 12(12)+22(1)+11(16)
= 144+22+176
= 342 g/mol
[tex]Moles=\frac{mass}{Molar\ mass}[/tex]
[tex]Moles=\frac{137.9}{342}[/tex]
[tex]Moles=0.403[/tex]
Moles = 0.403 moles
Mass of Solvent = 414.1 g (water)
[tex]Molality=\frac{moles\ of\ solute}{mass\ of\ solvent(g)}(1000)[/tex]
[tex]Molality =\frac{0.403}{414.1}\times 1000[/tex]
Molality = 0.973 m
