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Guinea Pigs can either have black fur (B) or white fur (b) and rough textured coats (R) or smooth textured coats (r).
If a guinea pig who is homozygous for both black fur and smooth texture is crossed with a white guinea pig who is heterozygous for rough texture, what are the expected phenotypic ratios for their offspring?
Group of answer choices: 0/16, 1/16, 8/16, 9/16, 3/16
black rough fur ...
black smooth fur ...
white rough fur ...
white smooth fur ...

Respuesta :

Answer:

The answers are explained below:

  1. Black rough fur - [tex]\frac{1}{2}=\frac{8}{16}[/tex].
  2. Black smooth fur - [tex]\frac{1}{2}=\frac{8}{16}[/tex].
  3. White rough fur - [tex]\frac{0}{16}[/tex].
  4. white smooth fur -[tex]\frac{0}{16}[/tex]

Explanation:

  • The genotype of homozygous black fur and smooth texture: BBrr.
  • The gametes produced are : Br
  • The genotype of white and  heterozygous for rough texture: bbRr
  • The gametes produced are : bR and br.
  • The cross,

                                                             bR        br

                                                    Br    BbRr     Bbrr

                                                           (B/R)   (B/S)

  • In the brackets (),
  1. B - Black.
  2. R - Rough.
  3. S -Smooth.
  • The cross can develop two types of offspring, that is,
  1. Black and Rough (BbRr) - 1.
  2. Black and smooth  (Bbrr)- 1.
  • The answers:
  1. Black rough fur - [tex]\frac{1}{2}=\frac{8}{16}[/tex].
  2. Black smooth fur - [tex]\frac{1}{2}=\frac{8}{16}[/tex].
  3. White rough fur - [tex]\frac{0}{16}[/tex].
  4. white smooth fur -[tex]\frac{0}{16}[/tex]