Answer : The condensed ground-state electron configuration for each is:
(a) [tex][Ar]4s^23d^{2}[/tex]
(b) [tex][Ne]3s^23p^5[/tex]
(c) [tex][Ar]4s^23d^{3}[/tex]
Explanation :
Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.
Number of electrons in an atom are determined by the electronic configuration.
Noble-Gas notation : It is defined as the representation of electron configuration of an element by using the noble gas directly before the element on the periodic table.
(a) The given element is, Ti (Titanium)
As we know that the titanium element belongs to group 4 and the atomic number is, 22
The ground-state electron configuration of Ti is:
[tex]1s^22s^22p^63s^23p^64s^23d^{2}[/tex]
So, the condensed ground-state electron configuration of Ti in noble gas notation will be:
[tex][Ar]4s^23d^{2}[/tex]
There are 4 number of valence electrons shown in orbital diagram.
(b) The given element is, Cl (Chlorine)
As we know that the chlorine element belongs to group 17 and the atomic number is, 17
The ground-state electron configuration of Cl is:
[tex]1s^22s^22p^63s^23p^5[/tex]
So, the condensed ground-state electron configuration of Cl in noble gas notation will be:
[tex][Ne]3s^23p^5[/tex]
There are 7 number of valence electrons shown in orbital diagram.
(c) The given element is, V (Vanadium)
As we know that the vanadium element belongs to group 5 and the atomic number is, 23
The ground-state electron configuration of Ti is:
[tex]1s^22s^22p^63s^23p^64s^23d^{3}[/tex]
So, the condensed ground-state electron configuration of V in noble gas notation will be:
[tex][Ar]4s^23d^{3}[/tex]
There are 5 number of valence electrons shown in orbital diagram.
