The volume (V) of the cone is 1/3 of the product of the area (A) of the base and height (h). The area of the circular base is, A = πd²/4. So,
V = πd²h/ 12
Substituting the given values,
V = π(12 in)²(9 in) / 12 = 108π in³
Thus, the volume of the cone is 108π in³.