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consider a charge of -15.0 mCmoving to the right a 2.00x10^6 m/s in a mganetic field of .0300 T pointing upwards. What is the magitude and direction of the force on this charge? If this charge had a mass of 8.00 x10^10kg what would be the acceleration be

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ohiekulous

Answer:

a = 1.13×10^-8 m/s²

Explanation:

[tex]f = ma = qvb \\ a = \frac{qvb}{m} [/tex]

q = 15×10^-3 C

v = 2×10^6 m/s

B = 0.03 T

m = 8.00 x10^10 kg

a = 900/8 x10^10

a = 1.13×10^-8 m/s²

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