Answer:
Step-by-step explanation:
Initial velocity of frank=45mph,
Now frank at a distance 1/3miles
Daniel started with a speed of 50mph,
Let Daniel catch up with Frank at time t
Speed = distance/time
Time=distance/speed
For frank, he has already traveled for a time of
t, =d/s
t=1/3÷50
t=1/150hour
Let now assume they meet at distance x,
Time for Daniel to reach x
t=d/s
t=x/50. Equation 1
Time for Frank to reach x, he has already traveled 1/3 miles, then he has x-1/3miles to travelled
t=d/s
t=(x-1/3)÷45. Equation 2
Then both time are same, let equate them
time frank =time Daniel
x/50=(x-1/3)/45
45x=50(x-1/3)
45x=50x-50/3
45x-50x=-50 /3
-5x=-50/3
x=50/3÷5
x=10/3
x=3.333miles
They will meet at 3.3333miles, not to know the time, let substitute into equation 1
t=x/50
t=3.33333/50
t=0.0667hours
Or t=4secs
