Respuesta :
From T = 2π√(l/g).
Since the lengths are the same, so that is a constant.
T α 1/√g
So the period T is inversely proportional to the square root of gravity g.
So the one with a bigger gravity g would have a shorter period
and
the one with smaller gravity g would have a longer period.
Therefore the period on the Moon with gravity of 1.63 m/s² would be longer period than that on the Earth with gravity of 9.81 m/s²
Since the lengths are the same, so that is a constant.
T α 1/√g
So the period T is inversely proportional to the square root of gravity g.
So the one with a bigger gravity g would have a shorter period
and
the one with smaller gravity g would have a longer period.
Therefore the period on the Moon with gravity of 1.63 m/s² would be longer period than that on the Earth with gravity of 9.81 m/s²
Answer:
The pendulum on the moon will have a longer period.
Explanation:
Just did it