Respuesta :
Answer:
Since the gene that transmits hemophilia is linked to the X chromosome ([tex]X^{h}[/tex]), for a couple to have a hemophiliac daughter, the father must present the disease and the mother must be a carrier. Therefore, the parents' genotypes are [tex]X^{h} Y[/tex] and [tex]X^{h} X[/tex], while the daughter and son genotypes are [tex]X^{h} X^{h}[/tex] and XY, respectively
Explanation:
An X-linked recessive gene -as in the case of hemophilia- will only be expressed in males with the affected X chromosome or in females who are homozygous for that gene.
- A healthy man and a carrier woman can have healthy, hemophilic sons, while half of the daughters could be carriers.
- A haemophiliac man and a healthy woman could have healthy sons and carrier daughters.
- A haemophiliac man and a carrier woman (as in the case above) can have healthy sons, while daughters can be carriers or haemophilics.
The cross between the hemophilic father and the carrier mother can be seen in the following diagram:
Alleles [tex]X^{h}[/tex] Y
[tex]X^{h}[/tex] [tex]X^{h} X^{h}[/tex] [tex]X^{h}[/tex]Y
X [tex]X^{h}[/tex]X XY
Where the possibility of having a healthy son and at least one daughter with hemophilia is evident.
Learn more:
Sex linked inheritance https://brainly.com/question/11839068
Answer:
It’s recessive. The mother who is a carrier is heterozygous, but she does not have the disease. The only offspring who have the disease are the boys who inherited one mutated gene.
Explanation:
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