Step-by-step explanation:
Since, opposite sides of a rectangle are equal and each angle is of 90°.
[tex] \therefore [/tex] QP = RS = 14 cm
[tex] In \:\triangle QPS, \: \angle QPS = 90\degree[/tex]
[tex] \therefore \: QS= \sqrt{QP^2+ PS^2} \\ \therefore \: QS= \sqrt{(14)^2+ (20)^2 } \\ \therefore \: QS= \sqrt{196 + 400} \\ \therefore \: QS= \sqrt{596} \\ \therefore \: QS= 24.41 \: m[/tex]
[tex] \because [/tex] Diagonals of a rectangle bisects each other.
[tex] \therefore\: QT = \frac{1}{2} QS\\
\therefore\: QT = \frac{1}{2} \times 24.41\\
\therefore\: QT =12.205\\
\huge\orange {\boxed {\therefore\: QT =12.21\:m}} [/tex]
