Answer:
0.5m(v1)²
Explanation:
We know that work done on an object is equal to the change in the kinetic energy of that object. Hence,
W. D = ΔK. E.
ΔK. E. = K. E.(final) - K. E.(initial)
Initial Kinetic energy, K. E.(initial), is:
K. E.(initial) = 0 (the box was at West)
Final K. E., K. E.(final) is:
K. E.(final) = 0.5*m*(v1)²
Hence, work done on the box will be:
W. D. = 0.5m(v1)² - 0
W. D. = 0.5m(v1)²
