Answer:
orange juice 0.80 dollar
Bagel 1 dollar
coffe 0.60 dollar
Explanation:
We construct the equation system:
[tex]\left \{ {A+B+C = 2.40} \atop {1.5A+1.2B+C = 3}} \right.[/tex]
We subtract one from another to get an expression without C:
1.5A+1.2B+C - (A+B+C) = 3 - 2.40
0.5A + 0.2B = 0.6
Then, we solve in the first part to express B as an expression of A
considering the coffe is worth half of the new cost of A
C = 1.5A / 2 = 0.75A
A + B + C = 2.40
A + B + 0.75A = 2.40
B = 2.40 - 1.75A
And now we replace in the other expression to get A:
0.5A + 0.2(2.40 - 1.75A) = 0.6
0.5A - 0.35A + 0.48 = 0.60
0.15A = 0.12
A = 0.12/0.15 = 0.8
Now we solve for C:
C = 0.75A = 0.6
Last, for B:
A + B + C = 2.40
0.8 + B + 0.6 = 2.40
B = 2.40 - 0.8 - 0.6 = 1