Trichloroethylene, a widely used degreasing solvent for machine parts, is produced in a two-step reaction sequence. Ethylene is first chlorinated to yield tetrachloroethane, which is dehydrochlorinated to form trichloroethylene.

C2H4 (g) + 2Cl2 (g) → C2H2Cl4 (l) + H2 (g): AHᵣ⁰ = -385.76 kJ
C2H2Cl4 (l) → C2HCl3 (l) + HCl (g)

The standard heat of formation of liquid trichloroethylene is -276.2 kJ/mol.
Use the given data and tabulated standard heats of formation of ethylene and HCl to calculate the standard heat of formation of tetrachloroethane and the standard heat of reaction for the second reaction.

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jufsanabriasa jufsanabriasa · Answer 1 · 2020-03-05T02:18:21+01:00

Answer:

ΔH°C2H2Cl4(l) = -333,36 kJ/mol

ΔH°r₂ = -35,14 kJ/mol

Explanation:

The ΔH°r of the first reaction is:

ΔH°r = -385,76 kJ/mol = (ΔH°C2H2Cl4(l) + ΔH°H2(g)) - (ΔH°C2H4(g) + 2ΔHCl2 (g))

ΔH°H2(g) = 0 kJ/mol

ΔH°C2H4(g) = 52,4 kJ/mol

Δ°HCl2 (g) = 0 kJ/mol

Replacing:

ΔH°C2H2Cl4(l) = -385,76 kJ/mol + 52,4 kJ/mol = -333,36 kJ/mol

The standard heat of the second reaction is:

ΔH°r₂ = ΔH°C2HCl3(l) + ΔH°HCl(g) - ΔH°C2H2Cl4(l)

Where:

ΔH°C2HCl3(l) = -276,2 kJ/mol; ΔH°HCl(g) = -92,3 kJ/mol; ΔH°C2H2Cl4(l) = -333,36 kJ/mol

Replacing:

ΔH°r₂ = -276,2 kJ/mol -92,3 kJ/mol + 333,36 kJ/mol

ΔH°r₂ = -35,14 kJ/mol

I hope it helps!