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A dog sledding team is composed of a 82.8 kg musher (the person driving the sled), a 21.4 kg sled, and four dogs. Assume that each dog's pull is fully transmitted to the sled, applied parallel to the ground, and the sled travels along level ground. How much power does each dog supply to pull the sled and driver system at a constant speed of 8.90 m/s if the coefficient of friction between the sled and the snow is 0.150

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Answer: 340.8W

Explanation: Please see the attachments below

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Ver imagen Abdulazeez10

Answer:

340.8 watt for each dog

Explanation:

Now, Work = Force x Displacement

We have to calculate power,

Now for power we will divide equation with time "t"

Work/time = Force x Displacement/time

So, equation becomes,

Power = Force x velocity

Now we  have to calculate net force acting upon system.

Net force = Force - Frictional force

Since, Coefficient of friction = F/N

Where F = force acting to slide and N = Normal force acting towards center of earth

Net Force = ma - (coefficient of friction x normal force)

now  0 = ma - 0.15 x {9.8 x (82.8 + 21.4)}

0 = (Force - 153.17) N

Force = 153.17 N

Notice that  "net force" will become "0" because velocity is constant.

So,

Power = Force x Velocity

Power = 153.17 x 8.9

Power = 1363.2 watt

Now for each dog

Power = 1363.2/4

Power = 340.8 watt

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