Answer:
[tex]-4.9\cdot 10^5 m/s^2[/tex]
Explanation:
The motion of the bullet is a uniformly accelerated motion, therefore we can find its acceleration by using the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the bullet in this problem:
u = 350 m/s is the initial velocity of the bullet
v = 0 is the final velocity (the bullet comes to a stop)
s = 0.125 m is the stopping distance of the bullet
Therefore, by solving the equation for a, we find its acceleration:
[tex]a=\frac{v^2-u^2}{2s}=\frac{0^2-350^2}{2(0.125)}=-4.9\cdot 10^5 m/s^2[/tex]
And the negative sign tells that the direction of the acceleration is opposite to that of the velocity.
