Respuesta :
Answer:
vf =2 m/s
Explanation:
Since the pieces of clay strike and stick together then they must move with the same velocity after the collision between them.
The conservation of momentum says that the initial and final momentum must be equal
[tex]Pinitial = Pfinal[/tex]
where [tex]Pinitial = m_{1} v_{1} + m_{2} v_{2}[/tex] and [tex]Pfinal = m_{1+2} v_{f}[/tex]
[tex]m_{1} v_{1} + m_{2} v_{2} = m_{1+2} v_{f}[/tex]
[tex]2*4 + 4*1 = (2+4) v_{f}[/tex]
[tex]12 = 6*v_{f}[/tex]
[tex]v_{f} =12/6[/tex]
[tex]v_{f} =2[/tex] [tex]m/s[/tex]
Therefore, the speed of the combined piece of clay is 2 m/s
Combined piece of clay will move with the speed of 2 meters per second.
Given in the question,
- 2 kg piece of clay moving with the speed 4 meter per sec.
- Another piece of clay of 4 kg is moving at a speed of 1 meter per second in opposite direction.
By the conservation of momentum,
[tex]m_1v_1+m_2v_2=mv[/tex]
Where [tex]m=m_1+m_2[/tex]
And 'v' = speed of the combined piece of clay
Therefore, equation will be,
[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]
Substitute the values from the question,
[tex]2\times 4+4\times 1=(2+4)v[/tex]
[tex]8+4=6v[/tex]
[tex]v=2[/tex] meter per sec.
Therefore, combined piece of clay will move with the speed of 2 meters per second.
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