Option B - y=-3(x+3)^2+6
Step-by-step explanation:
Step 1:
The equation of any parabola in the standard form with vertex at the origin is y^2 = 4ax . When it opens upward, the equation would be x^2 = 4ay
When the vertex is shifted to a point other than the origin, the equation would be
(x-h)^2 = 4a(y-k)
Step 2 :
Given that the vertex of the parabola is at (-3, 6). We will have the x and y co-ordinate shifted with this value.
So the equation of the parabola will have x and y shifted to x-(-3)) and y-6
=> x+3 and y-6
Step 3:
Based on the above 2, we can see that option B y=-3(x+3)^2+6 could be the equation of the parabola.
