Answer:
Energy stored in the spring when compressed 5.0 cm = 0.00146 J = 1.46 mJ
Explanation:
According to Hookes law,
F = kx
where F = force or load applied = 0.35 N
k = spring's constant = ?
x = extension or compression of the spring = 30 cm = 0.3 m
0.35 = k × 0.3
k = 0.35/0.3 = 1.167 N/m
Energy stored in a spring = kx²/2
k = 1.167 N/m, x = 5 cm = 0.05 m
Energy stored in the spring = (1.167)(0.05²)/2 = 0.00146 J = 1.46 mJ
