Answer:
[tex]-9.25 m/s^2[/tex]
Explanation:
The motion of the skater is a uniformly accelerated motion, so we can find the deceleration by using the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
In this problem, we have:
u = 19 m/s is the initial velocity of the skater
v = 18 m/s is the final velocity of the skater
s = 2.0 m is the displacement
Solving for a, we can find the acceleration:
[tex]a=\frac{v^2-u^2}{2s}=\frac{18^2-19^2}{2(2.0)}=-9.25 m/s^2[/tex]
And the negative sign tells us that the acceleration is in the opposite direction to the motion (so, it is a deceleration)
