contestada

The same potential difference is applied across two wires. Wire A carries twice thecurrent of wire B. If the resistance of wire B isR, what is the resistance of wire A?

Respuesta :

MechEngineer

Answer:

R / 2

Explanation:

According to Ohm law, the current flowing within the resistor is the ratio between the potential difference and the resistance:

[tex]I = \frac{V}{R}[/tex]

So if wire A carries twice the current of wire B, while their potential is the same then:

[tex]I_A = 2I_B[/tex]

[tex]\frac{V}{R_A} = \frac{2V}{R_B}[/tex]

[tex]R_B = 2R_A[/tex]

[tex]R_A = R_B / 2 = R / 2[/tex]

Otras preguntas