Respuesta :
Answer:
Momentum = 1.534 kgm/s
Explanation:
Using the equations of motion, we can obtain the velocity of the ball as it hits the ground.
g = 9.8 m/s²
y = 12 m
u = initial velocity = 0 m/s, since the ball was released from rest
v = final velocity befor the ball hits the ground.
v² = u² + 2ay
v² = 0 + 2×9.8×12 = 235.2
v = 15.34 m/s
The momentum at any point is given as mass × velocity at that point
Mass = 100 g = 0.1 kg, velocity = 15.34 m/s
Momentum = 0.1 × 15.34 = 1.534 kgm/s
Momentum is the product of the mass and velocity of an object. The momentum of the given ball is 1534 Kgm/s.
Momentum:
[tex]P = mv[/tex]
Where,
[tex]m [/tex]- mass - 100 g
[tex]v [/tex]- velocity
Velocity can be calculated by
[tex]v^2 = u^2 + 2ay[/tex]
Where,
[tex]u[/tex] - initial velocity = 0
[tex]v[/tex] - final velocity = ?
[tex]a[/tex] - acceleration = g
[tex]y[/tex] - height = 12 m
put the values in the formula,
[tex]v^2 = 0 + 2\times 9.8\times 12 \\\\ v = \sqrt {235.2}\\\\ v = 15.34 \rm \ m/s [/tex]
Put the value in the first equation,
[tex]p = 100 \times 15.34 \\\\ p = 1534 \rm \ Kgm/s[/tex]
Therefore, the momentum of the given ball is 1534 Kgm/s.
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