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Find the magnitude of the force F⃗ exerted by the leg on the small pulley. (By Newton's third law, the small pulley exerts an equal and opposite force on the leg.) Let the mass m be 2.27 kg.

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Memoona

Explanation:

As the small pulley and mass are not moving, they are stationary.

[tex]T_{2} = T_{1}[/tex] = mg = (2.27)(9.8)

                    = 22.246 N

Now resolve the force in the opposite direction.

F = 2Tcos30°

F = (2)(22.246)(cos30°)

F = 38.53 N

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