Answer: The daughter nuclide formed by the beta decay of given isotope is [tex]_{30}^{64}\textrm{Zn}[/tex]
Explanation:
Beta decay is defined as the process in which beta particle is emitted. In this process, a neutron gets converted to a proton and an electron.
The released beta particle is also known as electron.
[tex]_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta[/tex]
We are given:
Parent isotope = [tex]_{29}^{64}\textrm{Cu}[/tex]
The chemical equation for the beta decay process of [tex]_{29}^{64}\textrm{Cu}[/tex] follows:
[tex]_{29}^{64}\textrm{Cu}\rightarrow _{30}^{64}\textrm{Zn}+_{-1}^0\beta[/tex]
Hence, the daughter nuclide formed by the beta decay of given isotope is [tex]_{30}^{64}\textrm{Zn}[/tex]
